What is the maximum number of amps that a 40 VA, 120 V transformer with a 24 V secondary can carry?

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Multiple Choice

What is the maximum number of amps that a 40 VA, 120 V transformer with a 24 V secondary can carry?

To determine the maximum number of amps a 40 VA, 120 V transformer with a 24 V secondary can carry, we first need to understand the relationship between volts, amps, and volt-amperes (VA). The apparent power in volt-amperes (VA) is given by the formula: \[ \text{Power (P in VA)} = \text{Voltage (V)} \times \text{Current (I in Amps)} \] We know the transformer is rated for 40 VA, meaning it can deliver up to 40 volts times a certain current. Given that the secondary voltage is 24 V, we can rearrange the formula to solve for the current: \[ I = \frac{P}{V} \] Substituting in the known values: \[ I = \frac{40 \, \text{VA}}{24 \, \text{V}} \] Calculating this gives: \[ I = \frac{40}{24} \] \[ I = 1.6667 \, \text{A} \] When rounded, this approximates to 1.7 A. Thus, the correct answer is indeed 1.7 A, as this is the

To determine the maximum number of amps a 40 VA, 120 V transformer with a 24 V secondary can carry, we first need to understand the relationship between volts, amps, and volt-amperes (VA). The apparent power in volt-amperes (VA) is given by the formula:

[ \text{Power (P in VA)} = \text{Voltage (V)} \times \text{Current (I in Amps)} ]

We know the transformer is rated for 40 VA, meaning it can deliver up to 40 volts times a certain current. Given that the secondary voltage is 24 V, we can rearrange the formula to solve for the current:

[ I = \frac{P}{V} ]

Substituting in the known values:

[ I = \frac{40 , \text{VA}}{24 , \text{V}} ]

Calculating this gives:

[ I = \frac{40}{24} ]

[ I = 1.6667 , \text{A} ]

When rounded, this approximates to 1.7 A. Thus, the correct answer is indeed 1.7 A, as this is the

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